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SubjectRe: BUG: MAX_LOCKDEP_KEYS too low!
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On 23/01/2021 21:29, Tetsuo Handa wrote:
> On 2021/01/23 15:35, Alexey Kardashevskiy wrote:
>> this behaves quite different but still produces the message (i have show_workqueue_state() right after the bug message):
>>
>>
>> [   85.803991] BUG: MAX_LOCKDEP_KEYS too low!
>> [   85.804338] turning off the locking correctness validator.
>> [   85.804474] Showing busy workqueues and worker pools:
>> [   85.804620] workqueue events_unbound: flags=0x2
>> [   85.804764]   pwq 16: cpus=0-7 flags=0x4 nice=0 active=1/512 refcnt=3
>> [   85.804965]     in-flight: 81:bpf_map_free_deferred
>> [   85.805229] workqueue events_power_efficient: flags=0x80
>> [   85.805357]   pwq 4: cpus=2 node=0 flags=0x0 nice=0 active=1/256 refcnt=2
>> [   85.805558]     in-flight: 57:gc_worker
>> [   85.805877] pool 4: cpus=2 node=0 flags=0x0 nice=0 hung=0s workers=3 idle: 82 24
>> [   85.806147] pool 16: cpus=0-7 flags=0x4 nice=0 hung=69s workers=3 idle: 7 251
>> ^C[  100.129747] maxlockdep (5104) used greatest stack depth: 8032 bytes left
>>
>> root@le-dbg:~# grep "lock-classes" /proc/lockdep_stats
>>  lock-classes:                         8192 [max: 8192]
>>
>
> Right. Hillf's patch can reduce number of active workqueue's worker threads, for
> only one worker thread can call bpf_map_free_deferred() (which is nice because
> it avoids bloat of active= and refcnt= fields). But Hillf's patch is not for
> fixing the cause of "BUG: MAX_LOCKDEP_KEYS too low!" message.
>
> Like Dmitry mentioned, bpf syscall allows producing work items faster than
> bpf_map_free_deferred() can consume. (And a similar problem is observed for
> network namespaces.) Unless there is a bug that prevents bpf_map_free_deferred()
> from completing, the classical solution is to put pressure on producers (i.e.
> slow down bpf syscall side) in a way that consumers (i.e. __bpf_map_put())
> will not schedule thousands of backlog "struct bpf_map" works.


Should not the first 8192 from "grep lock-classes /proc/lockdep_stats"
decrease after time (it does not), or once it has failed, it is permanent?




--
Alexey

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