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Subject[PATCH 4.19 613/639] afs: Fix missing timeout reset
From: David Howells <>

[ Upstream commit c74386d50fbaf4a54fd3fe560f1abc709c0cff4b ]

In afs_wait_for_call_to_complete(), rather than immediately aborting an
operation if a signal occurs, the code attempts to wait for it to
complete, using a schedule timeout of 2*RTT (or min 2 jiffies) and a
check that we're still receiving relevant packets from the server before
we consider aborting the call. We may even ping the server to check on
the status of the call.

However, there's a missing timeout reset in the event that we do
actually get a packet to process, such that if we then get a couple of
short stalls, we then time out when progress is actually being made.

Fix this by resetting the timeout any time we get something to process.
If it's the failure of the call then the call state will get changed and
we'll exit the loop shortly thereafter.

A symptom of this is data fetches and stores failing with EINTR when
they really shouldn't.

Fixes: bc5e3a546d55 ("rxrpc: Use MSG_WAITALL to tell sendmsg() to temporarily ignore signals")
Signed-off-by: David Howells <>
Reviewed-by: Marc Dionne <>
Signed-off-by: Linus Torvalds <>
Signed-off-by: Sasha Levin <>
fs/afs/rxrpc.c | 1 +
1 file changed, 1 insertion(+)

diff --git a/fs/afs/rxrpc.c b/fs/afs/rxrpc.c
index 2543f24d23f8d..560dd5ff5a151 100644
--- a/fs/afs/rxrpc.c
+++ b/fs/afs/rxrpc.c
@@ -573,6 +573,7 @@ static long afs_wait_for_call_to_complete(struct afs_call *call,
call->need_attention = false;
+ timeout = rtt2;


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