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SubjectRe: [PATCH 08/12] mips: Dump memblock regions for debugging
On Wed, Apr 24, 2019 at 04:45:47PM +0300, Mike Rapoport wrote:
> On Wed, Apr 24, 2019 at 01:47:44AM +0300, Serge Semin wrote:
> > It is useful to have the whole memblock memory space printed to console
> > when basic memlock initializations are done. It can be performed by
> > ready-to-use method memblock_dump_all(), which prints the available
> > and reserved memory spaces if MEMBLOCK_DEBUG config is enabled.
>
> Nit: there's no MEMBLOCK_DEBUG config option but rather memblock=debug
> command line parameter ;-)
>

Right. Thanks. I'll reword the message in the next patchset revision.

-Sergey

> > Lets call it at the very end of arch_mem_init() function, when
> > all memblock memory and reserved regions are defined, but before
> > any serious allocation is performed.
> >
> > Signed-off-by: Serge Semin <fancer.lancer@gmail.com>
> > ---
> > arch/mips/kernel/setup.c | 2 ++
> > 1 file changed, 2 insertions(+)
> >
> > diff --git a/arch/mips/kernel/setup.c b/arch/mips/kernel/setup.c
> > index 2a1b2e7a1bc9..ca493fdf69b0 100644
> > --- a/arch/mips/kernel/setup.c
> > +++ b/arch/mips/kernel/setup.c
> > @@ -824,6 +824,8 @@ static void __init arch_mem_init(char **cmdline_p)
> > /* Reserve for hibernation. */
> > memblock_reserve(__pa_symbol(&__nosave_begin),
> > __pa_symbol(&__nosave_end) - __pa_symbol(&__nosave_begin));
> > +
> > + memblock_dump_all();
> > }
> >
> > static void __init resource_init(void)
> > --
> > 2.21.0
> >
>
> --
> Sincerely yours,
> Mike.
>

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