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Subject[Q] ld: Does LTO reorder ro variables in two files?

Hi, gcc guys,

this thread starts here:

There are two const variables:

struct sched_class idle_sched_class
struct sched_class fair_sched_class,

which are declared in two files idle.c and fair.c.

1)In Makefile the order is: idle.o fair.o
2)the variables go to the same ro section
3)there is no SORT(.*) keyword in linker script.

Is it always true, that after linkage &idle_sched_class < &fair_sched_class?


On 19.12.2019 16:12, Peter Zijlstra wrote:
> On Thu, Dec 19, 2019 at 03:39:14PM +0300, Kirill Tkhai wrote:
>> In kernel/sched/Makefile files, describing different sched classes, already
>> go in the order from the lowest priority class to the highest priority class:
>> idle.o fair.o rt.o deadline.o stop_task.o
>> The documentation of GNU linker says, that section appears in the order
>> they are seen during link time (see [1]):
>>> Normally, the linker will place files and sections matched by wildcards
>>> in the order in which they are seen during the link. You can change this
>>> by using the SORT keyword, which appears before a wildcard pattern
>>> in parentheses (e.g., SORT(.text*)).
>> So, we may expect const variables from idle.o will go before ro variables
>> from fair.o in RO_DATA section, while ro variables from fair.o will go
>> before ro variables from rt.o, etc.
>> (Also, it looks like the linking order is already used in kernel, e.g.
>> in drivers/md/Makefile)
>> Thus, we may introduce an optimization based on xxx_sched_class addresses
>> in these two hot scheduler functions: pick_next_task() and check_preempt_curr().
>> One more result of the patch is that size of object file becomes a little
>> less (excluding added BUG_ON(), which goes in __init section):
>> $size kernel/sched/core.o
>> text data bss dec hex filename
>> before: 66446 18957 676 86079 1503f kernel/sched/core.o
>> after: 66398 18957 676 86031 1500f kernel/sched/core.o
> Does LTO preserve this behaviour? I've never quite dared do this exact
> optimization.

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