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SubjectRe: [PATCH 2/2] PM / Sleep: Check the file capability when writing wake lock interface

> On Dec 31, 2018, at 5:33 AM, Greg Kroah-Hartman <> wrote:
>> On Mon, Dec 31, 2018 at 01:02:35PM +0100, Jann Horn wrote:
>> On Mon, Dec 31, 2018 at 11:41 AM Greg Kroah-Hartman
>> <> wrote:
>>>> On Mon, Dec 31, 2018 at 05:38:51PM +0800, joeyli wrote:
>>>> Hi Greg,
>>>>> On Sun, Dec 30, 2018 at 03:48:35PM +0100, Greg Kroah-Hartman wrote:
>>>>>> On Sun, Dec 30, 2018 at 09:28:56PM +0800, Lee, Chun-Yi wrote:
>>>>>> The wake lock/unlock sysfs interfaces check that the writer must has
>>>>>> CAP_BLOCK_SUSPEND capability. But the checking logic can be bypassed
>>>>>> by opening sysfs file within an unprivileged process and then writing
>>>>>> the file within a privileged process. The tricking way has been exposed
>>>>>> by Andy Lutomirski in CVE-2013-1959.
>>>>> Don't you mean "open by privileged and then written by unprivileged?"
>>>>> Or if not, exactly how is this a problem? You check the capabilities
>>>>> when you do the write and if that is not allowed then, well
>>>> Sorry for I didn't provide clear explanation.
>>>> The privileged means CAP_BLOCK_SUSPEND but not file permission. The file permission
>>>> has already relaxed for non-root user. Then the expected behavior is that non-root
>>>> process must has CAP_BLOCK_SUSPEND capability for writing wake_lock sysfs.
>>>> But, the CAP_BLOCK_SUSPEND restrict can be bypassed:
>>>> int main(int argc, char* argv[])
>>>> {
>>>> int fd, ret = 0;
>>>> fd = open("/sys/power/wake_lock", O_RDWR);
>>>> if (fd < 0)
>>>> err(1, "open wake_lock");
>>>> if (dup2(fd, 1) != 1) // overwrite the stdout with wake_lock
>>>> err(1, "dup2");
>>>> sleep(1);
>>>> execl("./string", "string"); //string has capability
>>>> return ret;
>>>> }
>>>> This program is an unpriviledged process (has no CAP_BLOCK_SUSPEND), it opened
>>>> wake_lock sysfs and overwrited stdout. Then it executes the "string" program
>>>> that has CAP_BLOCK_SUSPEND.
>>> That's the problem right there, do not give CAP_BLOCK_SUSPEND rights to
>>> "string". If any user can run that program, there's nothing the kernel
>>> can do about this, right? Just don't allow that program on the system :)
>>>> The string program writes to stdout, which means that it writes to
>>>> wake_lock. So an unpriviledged opener can trick an priviledged writer
>>>> for writing sysfs.
>>> That sounds like a userspace program that was somehow given incorrect
>>> rights by the admin, and a user is taking advantage of it. That's not
>>> the kernel's fault.
>> Isn't it? Pretty much any setuid program will write to stdout or
>> stderr; even the glibc linker code does so if you set LD_DEBUG.
>> (Normally the output isn't entirely attacker-controlled, but it is in
>> the case of stuff like "procmail", which I think Debian still ships as
>> setuid root.) setuid programs should always be able to safely call
>> read() and write() on caller-provided file descriptors. Also, you're
>> supposed to be able to receive file descriptors over unix domain
>> sockets and then write to them without trusting the sender. Basically,
>> the ->read and ->write VFS handlers should never look at the caller's
>> credentials, only the opener's (with the exception of LSMs, which tend
>> to do weird things to the system's security model).
> So a root program gets the file handle to the sysfs file and then passes
> it off to a setuid program and the kernel should somehow protect from
> this?

Yes, the kernel should. If the kernel wants to check caps, it should do it right.

Calling capable() from a .write handler is wrong, even in sysfs.

> I think that any sysfs file that is relying on the capable() check
> should just set their permissions properly first, and then it should be
> ok.

Probably true.

> thanks,
> greg k-h

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